7m^2-63m+56=0

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Solution for 7m^2-63m+56=0 equation:



7m^2-63m+56=0
a = 7; b = -63; c = +56;
Δ = b2-4ac
Δ = -632-4·7·56
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-49}{2*7}=\frac{14}{14} =1 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+49}{2*7}=\frac{112}{14} =8 $

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